evaluate $\displaystyle \int \dfrac{(x+1)e^x}{(x+2)^2} \, dx$
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$\displaystyle \dfrac{(x+1)e^x}{(x+2)^2}=\dfrac{(x+2-1)e^x}{(x+2)^2}=\dfrac{(x+2)e^x-e^x}{(x+2)^2}=\dfrac{d}{dx}\left( \dfrac{e^x}{x+2} \right)$
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