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- Dec 27th 2010, 11:25 PMr-soyquestion on derivative I wan chek
- Dec 28th 2010, 12:33 AMchisigma
The computation is easier if You take into account the identity...

$\displaystyle \displaystyle \frac{\sqrt{s}-1}{\sqrt{s}+1} = 1 - \frac{2}{\sqrt{s} +1}$

Kind regards

$\displaystyle \chi$ $\displaystyle \sigma$ - Dec 28th 2010, 01:18 AMr-soy
Is my answer no correct or not ?

- Dec 28th 2010, 02:34 AMHallsofIvy
No, it isn't.

You have the formula $\displaystyle \left(\frac{u}{v}\right)'= \frac{u'v- uv'}{v^2}$ correct but then you**used**$\displaystyle \frac{uv'- u'v}{v^2}$ which is wrong. - Dec 28th 2010, 03:04 AMProve It