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Once you have the slope, identify a point on the graph and use this formula $\displaystyle y-y_1=m(x-x_1)$
Originally Posted by r-soy You have miscalculated. $\displaystyle \displaystyle\ x^{-\frac{1}{2}}=\frac{1}{1.5}\Rightarrow\frac{1}{x^{\ frac{1}{2}}}=\frac{1}{\sqrt{x}}=\frac{1}{1.5}$ $\displaystyle \displaystyle\sqrt{x}=1.5\Rightarrow\ x=1.5^2$
Now X = 2.25 when I try found (y) I don't get the answer I don't now why >> y = (2.25) - 3 (2.25)^1/2 =-1.125 this answer not as on my book Also what is the range of values of curve's slop ? (-in,1] is this correct ? plese help me
Originally Posted by r-soy y = (2.25) - 3 (2.25)^1/2 =-1.125 this answer not as on my book check again, $\displaystyle y= 2.25-3\sqrt{2.25} = -2.25$
but when I do here different answer y = (2.25) - 3 (2.25)^1/2
$\displaystyle y= 2.25-3\sqrt{2.25}$ $\displaystyle y= 2.25-3\times 1.5$ $\displaystyle y= 2.25-4.5$ $\displaystyle y= -2.25$
I know my dear it will come in that equation but when I do here y = (2.25) - 3 (2.25)^1/2 I got diffrent answer .
What do you mean "when I do here"? Are you saying you get something other than 2.25 for y? If so you are doing the arithmetic wrong!
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