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Thread: Inverse Laplace Transform

  1. December 25th 2010, 09:53 PM #1
    kjchauhan
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    Inverse Laplace Transform

    Please help me to find an inverse Laplace Transform :

    L^{-1}\left(\frac{p}{(p^2+a^2)^2}\right)

    Thanks in advance..
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  2. December 25th 2010, 10:14 PM #2
    FernandoRevilla
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    Use the following:

    (i)\quad\mathcal{L}\{f(t)\}=F(p)\Rightarrow\mathca l{L}\{tf(t)\}=-\dfrac{d}{dp}F(p)

    (ii)\quad \mathcal{L}\{\sin bt\}=\dfrac{b}{p^2+b^2}


    Fernando Revilla
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