I have been asked to prove that a metric space has the Bolzano Weierstrass property if and only if it is complete and totally bounded.
It seems obvious to me that Bolzano Weierstrass implies completeness however unless I am mistaken the real line is a counterexample (with the Euclidean metric) to the statement.
R is not totally bounded and it satisfies the Bolzano Weierstrass property. Am I being stupid here? It is just that I was trying to do a past-paper question and this is what I am being asked to show.