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**Chokfull** I get $\displaystyle \frac{d}{dt}a(t)=\frac{\cos(\theta(t))\theta(1)}{\ sqrt{9-\sin(\theta(t))^2}}$

I'm not sure about this part, either...If i replace $\displaystyle \theta(t)$ with $\displaystyle \frac{\pi}{3}$, because $\displaystyle \theta=\frac{\pi}{3}$ is the point at which Im trying to find the speed, I get $\displaystyle .174*\theta(1)$. The correct answer is 6.563. This means that, for the equation above to be correct, $\displaystyle \theta(1)$ has to equal 37.718....Right? But this makes no sense :P