evalutate the double intergral (double intergral sign) (2x2+y+1)dA over the region R defined by x2<y<x and 0<x<1 much appreciated!
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Originally Posted by turion645344 evalutate the double intergral (double intergral sign) (2x2+y+1)dA over the region R defined by x2<y<x and 0<x<1 much appreciated! $\displaystyle \iint_R 2x^2 + y + 1 \ dA = \int_0^1 \int_{x^2}^x 2x^2 + y + 1 \ dy \ dx$ $\displaystyle \int_0^1 2x^2y+\frac{1}{2}y^2+y \big|_{x^2}^x dx$ $\displaystyle \int_0^1 2x^3 + \frac{1}{2}x^2+ x - 2x^4 - \frac{1}{2}x^4 - x^2 \ dx$ You can do it from there.
cheers, i then get $\displaystyle -2.5x^4 + 2x^3 - 0.5x^2 + x $ dx which when intergrating between 1 and 0 gives 2.5 - 2 + 0.5 -1 = 0
Last edited by turion645344; Jul 11th 2007 at 07:46 AM.
is then 2.5 - 2 + 0.5 -1 = 0 the right answer???
I get 1/3
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