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Math Help - double intergration 2

  1. #1
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    double intergration 2

    evalutate the double intergral

    (double intergral sign) (2x2+y+1)dA

    over the region R defined by x2<y<x and 0<x<1

    much appreciated!
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  2. #2
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    Quote Originally Posted by turion645344 View Post
    evalutate the double intergral

    (double intergral sign) (2x2+y+1)dA

    over the region R defined by x2<y<x and 0<x<1

    much appreciated!
    \iint_R 2x^2 + y + 1 \ dA = \int_0^1 \int_{x^2}^x 2x^2 + y + 1 \ dy \ dx

    \int_0^1 2x^2y+\frac{1}{2}y^2+y \big|_{x^2}^x  dx

    \int_0^1 2x^3 + \frac{1}{2}x^2+ x - 2x^4 - \frac{1}{2}x^4 - x^2 \ dx

    You can do it from there.
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  3. #3
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    cheers, i then get  -2.5x^4 + 2x^3 - 0.5x^2 + x dx

    which when intergrating between 1 and 0 gives

    2.5 - 2 + 0.5 -1 = 0
    Last edited by turion645344; July 11th 2007 at 08:46 AM.
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  4. #4
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    is then

    2.5 - 2 + 0.5 -1 = 0

    the right answer???
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  5. #5
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    I get 1/3
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