double intergration 2

**turion645344** · July 9th 2007, 08:37 AM

evalutate the double intergral

(double intergral sign) (2x2+y+1)dA

over the region R defined by x2<y<x and 0<x<1

much appreciated!

**ThePerfectHacker** · July 9th 2007, 08:51 AM

Originally Posted by turion645344

evalutate the double intergral

(double intergral sign) (2x2+y+1)dA

over the region R defined by x2<y<x and 0<x<1

much appreciated!

$\iint_R 2x^2 + y + 1 \ dA = \int_0^1 \int_{x^2}^x 2x^2 + y + 1 \ dy \ dx$

$\int_0^1 2x^2y+\frac{1}{2}y^2+y \big|_{x^2}^x dx$

$\int_0^1 2x^3 + \frac{1}{2}x^2+ x - 2x^4 - \frac{1}{2}x^4 - x^2 \ dx$

You can do it from there.

**turion645344** · July 10th 2007, 04:24 AM

cheers, i then get $-2.5x^4 + 2x^3 - 0.5x^2 + x$ dx

which when intergrating between 1 and 0 gives

2.5 - 2 + 0.5 -1 = 0

**turion645344** · July 11th 2007, 07:47 AM

is then

2.5 - 2 + 0.5 -1 = 0

the right answer???

**ThePerfectHacker** · July 11th 2007, 09:11 AM

I get 1/3

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