1. ## double intergration 2

evalutate the double intergral

(double intergral sign) (2x2+y+1)dA

over the region R defined by x2<y<x and 0<x<1

much appreciated!

2. Originally Posted by turion645344
evalutate the double intergral

(double intergral sign) (2x2+y+1)dA

over the region R defined by x2<y<x and 0<x<1

much appreciated!
$\iint_R 2x^2 + y + 1 \ dA = \int_0^1 \int_{x^2}^x 2x^2 + y + 1 \ dy \ dx$

$\int_0^1 2x^2y+\frac{1}{2}y^2+y \big|_{x^2}^x dx$

$\int_0^1 2x^3 + \frac{1}{2}x^2+ x - 2x^4 - \frac{1}{2}x^4 - x^2 \ dx$

You can do it from there.

3. cheers, i then get $-2.5x^4 + 2x^3 - 0.5x^2 + x$ dx

which when intergrating between 1 and 0 gives

2.5 - 2 + 0.5 -1 = 0

4. is then

2.5 - 2 + 0.5 -1 = 0