evaluate the intergral 3 2 (integral sign) (intergral sign) (2y3+6xy+x2+1)dydx 0 1 so its like 0<x<3 and 1<y<2 (i think) any help?!
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Originally Posted by turion645344 evaluate the intergral 3 2 (integral sign) (intergral sign) (2y3+6xy+x2+1)dydx 0 1 so its like 0<x<3 and 1<y<2 (i think) any help?! You can do it fron there.
when you take them away, i get 3 (intergration sign) x2+9x+8.5 dx 0 when 3 (1/3x3 + 9/2x2 + 8.5x) 0 and then 9+40.5+25.5 so an answer of 75.
Last edited by turion645344; Jul 11th 2007 at 07:47 AM.
the answer of 75. is this correct???
Originally Posted by turion645344 the answer of 75. is this correct??? Yes
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