working in (Real)^2
{(x, 0) : sin x ≥ 0}
I Know this set is closed but is unbouned. But i am finding it different to show this.
{(x^3y - z^2; xyz + y^3z) : 0 =< x, y,z =< 1).}
I finding it difficult to show this is closed.
Thanks for helping
working in (Real)^2
{(x, 0) : sin x ≥ 0}
I Know this set is closed but is unbouned. But i am finding it different to show this.
{(x^3y - z^2; xyz + y^3z) : 0 =< x, y,z =< 1).}
I finding it difficult to show this is closed.
Thanks for helping