f(x)= (e^x +1)^2

I am not sure how to find the derivative of this one!

Do I (e^x +1)(e^x +1)?

Thanks in advance!

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- Dec 16th 2010, 09:52 AMadvancedfunctions2010derivative of the function y=e^x
f(x)= (e^x +1)^2

I am not sure how to find the derivative of this one!

Do I (e^x +1)(e^x +1)?

Thanks in advance! - Dec 16th 2010, 09:55 AMsnowtea
Use the chain rule.

du^2/dx = 2u du/dx

Where u = e^x + 1 - Dec 16th 2010, 11:29 AMjanvdl
- Dec 16th 2010, 11:34 AMHallsofIvy
Or simply use the chain rule as snowtea suggested:

$\displaystyle f'(x)= 2(e^x+ 1)(e^x+1)'= 2(e^x+ 1)(e^x)= 2e^{2x}+ 2e^x$