How to solve, lim x--->0 x/ln(1+x). Thanks in advance!\ Say Khong God Bless.
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Originally Posted by saykhong How to solve, lim x--->0 x/ln(1+x). Thanks in advance!\ Say Khong God Bless. Limit is of the form: 0/0. Use L'Hôpital's rule.
Originally Posted by saykhong How to solve, lim x--->0 x/ln(1+x). Thanks in advance!\ Say Khong God Bless. $\displaystyle \displaystyle\ y=\frac{1}{x}\Rightarrow\ x\rightarrow\ 0,\;\;\;y\rightarrow\infty$ $\displaystyle \displaystyle\lim_{y \to \infty}\frac{1}{y\;ln\left[1+\frac{1}{y}\right]}=\lim_{y \to \infty}\frac{1}{ln\left[1+\frac{1}{y}\right]^y}=\frac{1}{ln(e)}=1$
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