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Math Help - partially solved line integral

  1. #1
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    partially solved line integral

    I have gotten a line integral this far and can't figure out how to integrate it. I solved it on an integral calc, which gave me the correct value, I just don't know how to do the steps.

    \int^1_0 2t^3 \sqrt[2]{1+4t^2+4t^4} dt
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  2. #2
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    \displaystyle 1+4t^2+4t^4=(2t^2+1)^2

    \displaystyle \int_0^1 (2t^3*(2t^2+1))dt

    Spoiler:
    \displaystyle \int_0^1 (4t^5+2t^3)dt=\left[\frac{2t^6}{3}+\frac{t^4}{2}\right]_0^1=\frac{2}{3}+\frac{1}{2}\right)=\frac{7}{6}
    Last edited by dwsmith; December 14th 2010 at 09:18 PM.
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  3. #3
    MHF Contributor matheagle's Avatar
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    It looks like you have two 2's, instead of one.
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  4. #4
    MHF Contributor matheagle's Avatar
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    ok, you killed that extra 2, but the upper bound was a 1 not a 2.
    you have a thing with 2's?
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  5. #5
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    You can never have enough 2's.
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