I have gotten a line integral this far and can't figure out how to integrate it. I solved it on an integral calc, which gave me the correct value, I just don't know how to do the steps.

$\displaystyle \int^1_0 2t^3 \sqrt[2]{1+4t^2+4t^4} dt$

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- Dec 14th 2010, 03:28 PMmanyarrowspartially solved line integral
I have gotten a line integral this far and can't figure out how to integrate it. I solved it on an integral calc, which gave me the correct value, I just don't know how to do the steps.

$\displaystyle \int^1_0 2t^3 \sqrt[2]{1+4t^2+4t^4} dt$ - Dec 14th 2010, 04:30 PMdwsmith
$\displaystyle \displaystyle 1+4t^2+4t^4=(2t^2+1)^2$

$\displaystyle \displaystyle \int_0^1 (2t^3*(2t^2+1))dt$

__Spoiler__: - Dec 14th 2010, 04:54 PMmatheagle
It looks like you have two 2's, instead of one.

- Dec 14th 2010, 08:16 PMmatheagle
ok, you killed that extra 2, but the upper bound was a 1 not a 2.

you have a thing with 2's? - Dec 14th 2010, 08:21 PMdwsmith
You can never have enough 2's.