Results 1 to 2 of 2

Math Help - y=(x^2+2x-1)^(1/2) find y'

  1. #1
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580

    y=(x^2+2x-1)^(1/2) find y'

    y=\sqrt{x^2+2x-1} find y^, answer in book is \frac{x+1}{y} but don't see how?

    I did this...

    y^, = \frac{1}{2}(x^2+2x-1)^{-\frac{1}{2}}(2x+2)<br /> <br />
\Rightarrow <br />
\frac<br />
{x+1}<br />
{(x^{2}+2x-1)^{\frac{1}{2}}}<br />
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Super Member bigwave's Avatar
    Joined
    Nov 2009
    From
    honolulu
    Posts
    580
    never mind I see what is in the denominator is y
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. Replies: 8
    Last Post: March 22nd 2011, 04:57 PM
  2. Replies: 2
    Last Post: July 5th 2010, 08:48 PM
  3. Replies: 1
    Last Post: February 17th 2010, 03:58 PM
  4. Replies: 0
    Last Post: June 16th 2009, 12:43 PM
  5. Replies: 2
    Last Post: April 6th 2009, 08:57 PM

Search Tags


/mathhelpforum @mathhelpforum