You should get
As you can see, what makes the numerator equal to 0?.
Find the coordinates of each point on the graph of the given function where the tangent line is horizontal.
I have this problem:
f(x)=(sqrt x)(x-3).
I used the product rule:
(sqrt x)(x-3)'+(sqrt x)'(x-3)
coming out (sqrt x)+x-3. I know this cannot be right.
What am I doing wrong with this?
The answer is suppose to be (1,-2).