But the answer is different.

Please help me finding which step is wrong.

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- December 14th 2010, 01:53 AMkumaran5555Problem in integration

But the answer is different.

Please help me finding which step is wrong. - December 14th 2010, 02:05 AMe^(i*pi)
According to Wolfram you forgot the constant of integration:

The only real question I have is in the third line you've automatically assumed that when multiplying by x^2/x^2 - December 14th 2010, 02:07 AMProve It

.

Now for the first make the substitution and for the second make the substitution . - December 14th 2010, 02:24 AMkumaran5555
- December 14th 2010, 02:35 AMe^(i*pi)
- December 14th 2010, 02:38 AMkumaran5555
Thanks.

So, I should not proceed with the approach I have used.

Am I correct? - December 14th 2010, 02:41 AMProve It
- December 14th 2010, 02:44 AMkumaran5555
- December 14th 2010, 02:52 AMkumaran5555
- December 14th 2010, 03:01 AMe^(i*pi)
It will still be undefined when x=0. It would be fine if 0 wasn't in the original domain but because it is you're still potentially dividing by 0. This means that x=0 is a potential solution. In your equation let then

You can do it if you exclude 0 from the domain - December 14th 2010, 03:07 AMkumaran5555
So, I am taking it as if any function which has zero in its domain, doing will result in undefined value. So it should not be done.

- December 14th 2010, 04:14 AMe^(i*pi)
Yeah, that's it. Quite frustrating I admit