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About LinkBacksi big idiot i couldnīt count this task ....Could anyone help me please?
y = sinx
x = 0
x = π around the x axis
http://www.sdilej.eu/pics/9ee44f5f2f1c9 ... c915dc.jpg
outcome is 1/2 Π^2
i big idiot i couldnīt count this task ....Could anyone help me please?
y = sinx
x = 0
x = π around the x axis
http://www.sdilej.eu/pics/9ee44f5f2f1c9 ... c915dc.jpg
outcome is 1/2 Π^2
So basically you don't know how to evaluate:right? You have to use a trig identity.
integral of sine squared
So you should obtain![\pi\left[\frac{x}{2}-\frac{1}{4}sin(2x)\right]_0^{\pi}=\frac{\pi^2}{2}](http://latex.codecogs.com/png.latex?\pi\left[\frac{x}{2}-\frac{1}{4}sin(2x)\right]_0^{\pi}=\frac{\pi^2}{2})
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