Good Day,
I'm faced with a partial fractions and integration problem I've attached. I got the partial fractions part right.But I just can't get the final answer for the integration part.
Help need. Thanks.
For example,
$\displaystyle -\dfrac{1}{4}\displaystyle\int \dfrac{dx}{-1-x}=\dfrac{1}{4}\left[\log |x+1|\right]_{-10}^{-8}=\dfrac{1}{4}(\log 7-\log 9)=\dfrac{1}{4}\log \dfrac{7}{9}\quad[1]$
$\displaystyle \dfrac{1}{4}\displaystyle\int \dfrac{dx}{1-x}=\ldots =\dfrac{1}{4}\log \dfrac{11}{9}\quad [2]$
Now, $\displaystyle [1]+[2]$ ...
Fernando Revilla
Thank you.
I was half asleep when I posted this, so I didn't actually state what I had a problem with exactly.
When I expressed it in partial fractions, I expressed it as (1/4) / (x+1) instead of (-1/4) / (-1-x).
However, when evaluating it in the integration part, I first left that part out as a log or ln for a negative number does not exist.
Then, after I saw the answer, I tried by taking the -1 out of (x+1). In the end, I ended up with (1/4) ln (81/77).
Now I realise that I left out one tiny thing that messed up my calculations .... the modulus sign