Attachment 20073

Stuck on these questions would appreciate the help very much!!!

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- December 12th 2010, 01:02 PMstudent31413 Interesting Questions
Attachment 20073

Stuck on these questions would appreciate the help very much!!! - December 12th 2010, 01:16 PMtonio
- December 12th 2010, 01:21 PMstudent3141
ive been trying but im tottaly stuck dont know where to begin! or how to approach it

- December 13th 2010, 12:04 AMmr fantastic
- December 13th 2010, 12:33 AMstudent3141
Ok i did question 7

8) i tried to get the mvt for both sides, do i treat the ln(x) and the RHS as seperate? and do i then juss find the mvt for both sides? cause when i try and get the mvt for the RHS i get 3/8 i think thats wrong isnt it supposed to be between 1 and 2??

9) This question i kno its implicit differentiation but what should i do with the A B C ???

I cant seem to find similar questions in text book... help needed!! - December 13th 2010, 12:45 AMProve It
Treat as constants.

- December 13th 2010, 01:09 AMstudent3141
For question 9 this is wat i did help!

2Ax + 2By(dy/dx) = 0

Dy/Dx = Ax/By

D^2y/Dx^2 = ByA - BAx(dy/dx) / (B^2).(y^2)

= BA(y-x(dy/dx)) / (B^2).(y^2)

whats going on????? did i do something wrong? - December 13th 2010, 01:14 AMProve It

.

To find you need to use the Quotient Rule... Also remember that you already know what is so you can substitute it in... - December 13th 2010, 01:24 AMstudent3141
http://upload.wikimedia.org/math/a/c...7302faea9a.png

btw thanks for the help

Thats quotient rule so:

dy/dx = - Ax/By

= - (ByA - AxB(dy/dx))/(B^2).(y^2)

= BA ( y - x(dy/dx))/(B^2).(y^2)

i get stuck over here - December 13th 2010, 01:31 AMProve It
Be more careful with what you write, in this step you're finding , not .

Also, you forgot to bring the negative down into your last step.

Now, assuming you had brought the negative down...

- December 13th 2010, 01:59 AMstudent3141
AHHH yess i get it now thank you so much!

Btw did you use a program to write that working out ? looks much more neater than what i was doing!

For question 8

(3/2)x - (1/4)x^2 - (5/4)

F(2)-F(1) / 2-1 = 3/4

dy/dx = 3/2 - (1/2)x

3/4 = 3/2 - (1/2)c

c= 3/2

ok so do i now juss work out the mvt of ln(x)??? - December 13th 2010, 04:39 AMProve It
I'm using the LaTeX compiler that is built into the forum.

See the LaTeX help subforum to learn how to use it.