Thread: Surface Area Calc 3

My problem says find the surface area of the part of the surface
z=y^2-x^2 that is inside the cylinder x^2+y^2=2

So im thinking of polar coordinates
saying f(x,y)=y^2-x^2
and fx=-2x, fy=2y
and the area=
double integral of (sqrt(1+4x^2+4y^2))

but my problem is how to go about finding the limits
Im not sure exactly, can i get direction so i can learn

Originally Posted by begin

My problem says find the surface area of the part of the surface
z=y^2-x^2 that is inside the cylinder x^2+y^2=2

So im thinking of polar coordinates
saying f(x,y)=y^2-x^2
and fx=-2x, fy=2y
and the area=
double integral of (sqrt(1+4x^2+4y^2))

but my problem is how to go about finding the limits
Im not sure exactly, can i get direction so i can learn

The part of the surfact that is it inside the cylindar is above the disk

and yes polar coordinates will be the best system.

If your integrating from 0-2pie first,
would the limits of integration be the other way?

Originally Posted by begin

If your integrating from 0-2pie first,
would the limits of integration be the other way?

You are correct. I have fixed the above post.

okk all done, thanks for the help...