We have:
and
is divergent, so the given series is also divergent.
Fernando Revilla
does series (n= 1 --> inf) sqrt(n)/(4n + 9) converge or diverge?
I said that it does converge, and I used the comparison test with b(sub n) = n/(4n + 9) got the limit at (1/4) for b(sub n). But the back of the book said I was wrong, what did I do wrong?
my steps: 0 < a(sub n) < b(sub n)
b(sub n) converges as limit approaches infinity, so doesn't that mean a(sub n) converges?
Thanks for any input. Sorry I did not use latex on this.
We have:
and
is divergent, so the given series is also divergent.
Fernando Revilla
Certainly your post responds better than mine to Warrenx's question. I didn't pay attention.
Fernando Revilla