1. ## Integration Correct?

Can someone check to see if my integration is correct experienced integrators.

Cant use this latex view attachment

2. You can't possibly have even set up the double integral properly - if you are integrating with respect to $\displaystyle y$ first then your innermost bounds need a function of $\displaystyle x$, not $\displaystyle y$.

3. i meant to switch the order of integration on the first equation
dxdy..

4. You can't do the integration with respect to $\displaystyle x$ first since there is not a closed form for the integral of $\displaystyle \frac{e^{x^2}}{x^3}$. Again, please post the entire original question.

5. I thought you can change the limits of integration to
0-4,0-x^2 dydx

6. ummm no Prove it is correct. You have written

$\int_{0}^{4}\int_{\sqrt{y}}^{2}\frac{ye^{x^2}}{x^3 }dydx$

Do you See the problem with what you posted. You are integrating with respect to y first and have it as a function of y. That does not make sense. After integration you would still have y's in your integrand but no y differential.