Theres the question:
A person shoots an arrow which leaves the bow at 4ft above the ground with an initial velocity of 88ft second at an elevation angle of 48*.
Will the arrow go over a 40 foot wall that is 200' away?
Theres the question:
A person shoots an arrow which leaves the bow at 4ft above the ground with an initial velocity of 88ft second at an elevation angle of 48*.
Will the arrow go over a 40 foot wall that is 200' away?
Um... I will use kinematics to solve this.
The vertical component of the arrow is
The horizontal component of the arrow is
So, the time it takes to cover 200 ft is 200/58.9 = 3.40 s.
Now, use the formula
with t = 3.40,
u = 65.4 ft/s
a = -9.8 m/s^2 (you will have to convert to ft/s^2)
and solve for s.
If s < (40 - 4), then the arrow won't pass. Otherwise, it will.
What did you get?
Hello, av8!
It certainly helps if you know the Trajectory Equations.
. . . . .
. . . . .
. . where: .
We are given: .
Our equations are:
. .
. .
The question is: When , is ?
When , we have:
. .
It takes about 3.4 seconds to travel 200 feet horizontally.
When , we have:
. .
Yes, the arrow will clear the wall.