How do you write the following equations in polar form z=re^io and find the values. Then write the answer in cartesian form x+iy

√(1-i√3)

cube√(-4(√2)+4√(2i))

*Sorry, I posted this in the wrong thread earlier.

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- December 9th 2010, 05:52 AMmariasmiles25Help with complex numbers in polar and cartesian form
How do you write the following equations in polar form z=re^io and find the values. Then write the answer in cartesian form x+iy

√(1-i√3)

cube√(-4(√2)+4√(2i))

*Sorry, I posted this in the wrong thread earlier. - December 9th 2010, 06:11 AMTheEmptySet
- December 9th 2010, 06:14 AMPlato
Let me be candid. I am in the camp of those who do not like the notation , i.e. using the radical sign in this way.

We prefer asking for the square roots of .

so the first square root is .

We know that so add that to the argument of the first root to get the second square root.

To get the cube roots divide by three instead of two. There are three roots.