I cannot get the right integral for the following function, help or hints would be appreciated. $\displaystyle \int\frac{\sqrt{x}}{x+1}dx$
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Originally Posted by iPod I cannot get the right integral for the following function, help or hints would be appreciated. $\displaystyle \int\frac{\sqrt{x}}{x+1}dx$ Try the substitution $\displaystyle x=u^2\Longrightarrow dx=2ydy$ and etc. Tonio
OH rite, I see where i was going wrong, i managed to get $\displaystyle 2\sqrt{x}+2atan(\sqrt{x})+C$ ^i believe that is correct?
Originally Posted by iPod OH rite, I see where i was going wrong, i managed to get $\displaystyle 2\sqrt{x}+2atan(\sqrt{x})+C$ ^i believe that is correct? Indeed...if by "atan" you actually meant "arctan". But you don't need to ask: just derivate the result and confirm you get the original function in the integral. Tonio
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