Find all complex numbers z, which satisfy z^(2)= i - 1.
I have come across this question during my tutorial and I cant seem to solve it. I need some reference. Thank you---> to the kind soul who is able to help me out here... =D
God Bless.
Find all complex numbers z, which satisfy z^(2)= i - 1.
I have come across this question during my tutorial and I cant seem to solve it. I need some reference. Thank you---> to the kind soul who is able to help me out here... =D
God Bless.
Exponential equations are easiest to solve when you put the complex numbers in exponential form. Remember that the are always 2 square roots, 3 cube roots, 4 fourth roots, etc, and they are all evenly spaced around a circle.
So for square roots, they are separated by an angle of .
Anyway, .
.
So that means .
Therefore,
.
That is the first square root. The second has an extra added to its angle. So the other square root is
.