Hi, I am having trouble with contours, is there a procedure to do these?
the question I am working on is when z=c
what i tried to do:
and that is where I got stuck. I cant visualize what is going on here
thanks for any replys :)
Well, it looks like its close to a circle because of its form. As c increases radius increases and x gets displaced.
sounds like 2 cones with a slope, how would i find a slope?
Calc II, contours
Yes! For any fixed value of c, is the equation of a circle with radius, c, centered on the x-axis at x=c. This circle passes through the origin.
Originally Posted by jameskw
When looked at in a more general way, is a family of such circles.
Therefore, the equation, , describes a pair of oblique circular cones, each with a vertex at
(0, 0, 0) and axis along the line in the x-z plane. One opens upward, the other downward.
You can also look at this as a pair of right elliptical cones, each with a vertex at (0, 0, 0) and axis along the line in the x-z plane. (I haven't figured out the eccentricity of the ellipses.)
Now "complete the square": , ,
a circle with center at (c, 0) and radius c so it is tangent to the y-axis at (0, 0).