Thread: give an equation for the plane that is parallel to the plane....

give an equation for the plane that is parallel to the plane 5x-4y+z=1 and that passes through the point (2,-1,-2).

i used the formula

f(a,b) + fx(a,b)(x-a) + fy(a,b)(y-b) + fz(a,b)(z-c)

and get

(-5x+4y+1) + (-5)(x-2) + (4)(y+1) + (1)(z+2)

then plug in the points for the rest of the variables

-13 + (-5x+10) + (4y+4) + (z+2)

-5x+4y+z+3


i'm pretty sure this is wrong and i'm not sure if i used the right formula for this. can anyone explain to me how to do this? is there a simpler way? thanks!

You are making it far too hard.
. DONE!

Originally Posted by break

Give an equation for the plane that is parallel to the plane 5x-4y+z=1 and that passes through the point (2,-1,-2).

i used the formula

f(a,b) + fx(a,b)(x-a) + fy(a,b)(y-b) + fz(a,b)(z-c)

and get

(-5x+4y+1) + (-5)(x-2) + (4)(y+1) + (1)(z+2)

then plug in the points for the rest of the variables

-13 + (-5x+10) + (4y+4) + (z+2)

-5x+4y+z+3


I'm pretty sure this is wrong and i'm not sure if i used the right formula for this. Can anyone explain to me how to do this? is there a simpler way? thanks!

Any plane parallel to the plane, will be of the form:

,

where is a constant. To find what that constant is, plug in the coordinates of any point in the plane.

That's basically what Plato did in one step.

wow... thanks for clearing this up!!