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Math Help - give an equation for the plane that is parallel to the plane....

  1. #1
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    give an equation for the plane that is parallel to the plane....

    give an equation for the plane that is parallel to the plane 5x-4y+z=1 and that passes through the point (2,-1,-2).

    i used the formula

    f(a,b) + fx(a,b)(x-a) + fy(a,b)(y-b) + fz(a,b)(z-c)

    and get

    (-5x+4y+1) + (-5)(x-2) + (4)(y+1) + (1)(z+2)

    then plug in the points for the rest of the variables

    -13 + (-5x+10) + (4y+4) + (z+2)

    -5x+4y+z+3


    i'm pretty sure this is wrong and i'm not sure if i used the right formula for this. can anyone explain to me how to do this? is there a simpler way? thanks!
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  2. #2
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    You are making it far too hard.
    5x-4y+z=5(2)-4(-1)+1(-2). DONE!
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  3. #3
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    give an equation for the plane that is parallel to the plane....

    Quote Originally Posted by break View Post
    Give an equation for the plane that is parallel to the plane 5x-4y+z=1 and that passes through the point (2,-1,-2).

    i used the formula

    f(a,b) + fx(a,b)(x-a) + fy(a,b)(y-b) + fz(a,b)(z-c)

    and get

    (-5x+4y+1) + (-5)(x-2) + (4)(y+1) + (1)(z+2)

    then plug in the points for the rest of the variables

    -13 + (-5x+10) + (4y+4) + (z+2)

    -5x+4y+z+3


    I'm pretty sure this is wrong and i'm not sure if i used the right formula for this. Can anyone explain to me how to do this? is there a simpler way? thanks!

    Any plane parallel to the plane, 5x-4y+z=1 will be of the form:

    5x-4y+z=D,

    where D is a constant. To find what that constant is, plug in the coordinates of any point in the plane.

    That's basically what Plato did in one step.
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  4. #4
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    wow... thanks for clearing this up!!
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