Show that f(x) = x^3 is continuous at 1 (from the definition)

(For all epsilon >0) (There exists delta >0) (For all x E X) if |x-1| < delta this implies

|x^3 - 1^3| < epsilon

|x^3 - 1^3| = |x-1| |x^2 + x + 1|

I've not got any further with this. Could I grab some help!