then u"(x) is calculated as
How was this derived?
I calculate both u'(x) and u"(x) to be equal to Ae^x. I dont know how the A^2 appears in front of u(x)!!!.....
[QUOTE=bugatti79;591430]My lecture notes reads
This is wrong. If then not .
Are you sure you don't have something like instead?????
I dont understand the third line!!...I dont think its the standard way of getting solution for a nd order equation?
If , then so .
By the way, using two consecutive single quotes in LaTex rather than a double quote will give rather than .