Hello I am getting stuck on how to prove the limit sin x / x = 1 as x ->0 with epsilon delta.

I have abs abs((sin x / x) -1)< epsilon and since sin x / x will always be less then 1 it would just become (1- sin x / x) < epsilon right?

also abs(x - a) < delta would just be abs(x) < delta since a = 0.

The goal now is to get the inequality with epsilon simplified to just x?