Please help me in finding the range of this equation.

5y(x-109x-3) = 2(5x+3)

I already got the domain which is x≠ 1,3.

My problem is on how to get the range. This is what I started.

5y(x-109x-3) = 2(5x+3)

5y(x^2-4x+3) = 10x+15

I stuck until here. I don't know if I did the right move.

A friend told me that the range is y≤-5 but he could not show me the whole solution.