$\displaystyle \lim x \rightarrow \infty \sqrt[3]{x^3 - 9x^2} - x$
If it weren't for that -x at the end, I'd just use Ln and L'Hopital's Rule if I needed to, but that -x throws me off. Not really sure how to get started...
$\displaystyle \lim x \rightarrow \infty \sqrt[3]{x^3 - 9x^2} - x$
If it weren't for that -x at the end, I'd just use Ln and L'Hopital's Rule if I needed to, but that -x throws me off. Not really sure how to get started...