One does not need an integral to find the average rate of change of a function.
The average rate of change of on is .
I will take Jhevon's advice and ask as many questions as I want. I am having trouble with a problem. The problem is:
What is the average rate of change of the function defined by on the interval ?I know the average value of a function to be so I assume that the average value of the rate of change of the function is given by which is just . Is my reasoning correct?
Which is just what I did. So the average value of a function ?
What would the average value of a function's integral be in the closed interval ? ? Or does it make no sense to take the average value of an integral? If it does, are there any applications you know of? Thanks