If f'(x) = (-4x^2-2x)/(x^4) and f(1)=3, find f(x). what i did:
antiderivative[(-4 x x^-2)-(2 x x^-3)]dx
= (-4 x x^-1)-(2 x -1/2x^-2)]
= (4/x)+(1/x^2)
= (4/(1))+(1/(1)^2)
=5
i get 5 but shouldn't the answer be 3? what did i do wrong!
If f'(x) = (-4x^2-2x)/(x^4) and f(1)=3, find f(x). what i did:
antiderivative[(-4 x x^-2)-(2 x x^-3)]dx
= (-4 x x^-1)-(2 x -1/2x^-2)]
= (4/x)+(1/x^2)
= (4/(1))+(1/(1)^2)
=5
i get 5 but shouldn't the answer be 3? what did i do wrong!