Hello! I am having problem solving this one: ∫ -y/(x^2+y^2)dx ∫t* sqrt(1+4t^2) dt Finding g(x) in the following equation: (g'(x)-g(x))x sin xy = 0
Follow Math Help Forum on Facebook and Google+
Originally Posted by tinyone Hello! I am having problem solving this one: ∫ -y/(x^2+y^2)dx Think of trigonometric functions. You'll have to use Inverse tangent function here.. Originally Posted by tinyone ∫t* sqrt(1+4t^2) dt Use the substitution rule.. let $\displaystyle u=4t^2+1$ show your work if you are having any problems.
View Tag Cloud