y'' - 2y' +5y = e^X cos(2x) im just a bit lost on this one...i know the sub will be Ae^x cos 4x + B e^x sin 4x ....
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Originally Posted by neven87 y'' - 2y' +5y = e^X cos(2x) im just a bit lost on this one...i know the sub will be Ae^x cos 4x + B e^x sin 4x .... no, we will guess a particular solution of the form: since the homogeneous solution is of the form we can't choose that as the particular solution, you'll end up with zero, so we add a factor of x
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