The derivative gives the slope of the tangent line, so let's find it first.Find the equation for the tangent line to at
At , we get:
Now let's find the point we want to work on.
So using the and
We have by the point-slope form:
The answer you gave is incorrect. That would be the answer if we wanted it at
I leave these to you, they are very similar. The difference with the normal line is that it is perpendicular to the tangent line. So when you find the slope of the tangent line, take it's negative inverse and use that as the slope for the normal line(2) Find the equation for the tangent line to f(x)= 1/(x+3) at x=2. ans. x+25y-7=0
3) Find the normal line to f(x)=1/(x+3) at x=3. ans 216x-6y-647=0