How do you this one?
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Let u=x+3 v'=sqrt(4-x^2)
More detail please..
Originally Posted by camherokid More detail please.. TPH is suggesting integration by parts. see your other post on integration by parts to see the full method i would expand the brackets first though, since the question says to write it as two integrals
I guess the integral is int((3+x)*sqrt(4-x^2),x=-2..2)).
Originally Posted by curvature I guess the integral is int((3+x)*sqrt(4-x^2),x=-2..2)). Then we have the following:
Originally Posted by curvature I guess the integral is int((3+x)*sqrt(4-x^2),x=-2..2)). No one can integrate (3+x)*sqrt(4-x^4) by hand.
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