Calculating gradient

**RespeckKnuckles** · November 24th 2010, 08:47 PM

Need to calculate the gradient of the following function:
$<br /> f(x,y) = x^2 + 2y^2 + 2\sin (2\pi x)\sin (2\pi y)<br />$

Here's what I got:

$<br /> \nabla f(x,y) = 2x + 2y + 4\pi [\sin (2\pi x)\sin (2\pi y) \cos (2\pi x) \cos (2\pi y)]<br />$

But being as this is my first time doing gradient calculations (need it for a course and I never took calculus 3, so this is self taught) I want to make sure it's right before I move on. Can someone double check for me?

**dwsmith** · November 24th 2010, 09:33 PM

$\displaystyle \nabla f(x,y)=(2x+4\pi cos(2\pi x)sin(2\pi y))i+(2+4\pi sin(2\pi x)cos(2\pi y))j$

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