Originally Posted by
ImaCowOK "A stone is thrown straight up from the edge of a roof, 725 feet above the ground, at a speed of 10 feet per second."
"A. Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later?"
I don't fully understand how to do these problems, the basic idea and steps. I have:
dv/dt = -32 I think I have to take the antiderivative of this which would be:
v = -32t + C
I'm not sure what to do afterwards because I don't understand the basic steps behind solving these types of problems. I'm trying to follow the textbook, but it's confusing. There's more parts to the question after this, but I can't study because I don't understand.