• June 30th 2007, 06:15 AM
janvdl
Jhevon did explain this to me, i think, but i forgot it again.

Let's say we want to find the derivative of $sin^3 (5x^2 - 4x)$

now that becomes $3(sin(5x^2 - 4x))^2 . cos(5x^2 - 4x) . (10x - 4)$

But if it was just $sin(5x^2 - 4x)$ would it have become:

$cos(5x^2 - 4x) . (10x - 4)$ ?
• June 30th 2007, 06:30 AM
topsquark
Quote:

Originally Posted by janvdl
Jhevon did explain this to me, i think, but i forgot it again.

Let's say we want to find the derivative of $sin^3 (5x^2 - 4x)$

now that becomes $3(sin(5x^2 - 4x))^2 . cos(5x^2 - 4x) . (10x - 4)$

But if it was just $sin(5x^2 - 4x)$ would it have become:

$cos(5x^2 - 4x) . (10x - 4)$ ?

Jhevon must have done a good job at explaining it. (No great surprise!) You did it perfectly.

-Dan