dy/dx=e^(x-y) This statement must be true y(0)=5
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You need to solve this differential equation? $\displaystyle \dfrac{dy}{dx} = e^{x-y}$ $\displaystyle \dfrac{dy}{dx} = \dfrac{e^x}{e^y}$ $\displaystyle \displaystyle \int e^y\ dy = \int e^x\ dx$
Thanks man ur awesome
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