Moderator edit: Restored deleted question. Thread closed.
If $\displaystyle f(x)= \frac{x^3(x- 2)^3}{(x^2+ 8)^7}$
then $\displaystyle ln(f(x))= 3 ln(x)+ 3ln(x- 2)- 7 ln(x^2+ 8)$
So that $\displaystyle \frac{1}{f(x)}\frac{df}{dx}= $ the derivative on the right.
To find $\displaystyle \frac{df}{dx}$ differentiate on the right and multiply by $\displaystyle f(x)= \frac{x^3(x- 2)^3}{(x^2+ 8)^7}$.