Help on log derivation

• November 19th 2010, 07:39 AM
softballchick
Help on log derivation

Moderator edit: Restored deleted question. Thread closed.
• November 19th 2010, 07:47 AM
harish21
what have you tried?

Hint: write $x^3(x-2)^3 = (x(x-2))^3=(x^2-2x)^3$

so have $\dfrac{x^3(x-2)^3}{(x^2+8)^7} = (x^2-2x)^3\; (x^2+8)^{-7}$

use the product rule!
• November 19th 2010, 07:48 AM
TheCoffeeMachine
Quote:

Originally Posted by softballchick

Are we to assume that you're required to find the derivative by logarithmic differentiation? It isn't clear!
• November 19th 2010, 12:37 PM
HallsofIvy
If $f(x)= \frac{x^3(x- 2)^3}{(x^2+ 8)^7}$

then $ln(f(x))= 3 ln(x)+ 3ln(x- 2)- 7 ln(x^2+ 8)$

So that $\frac{1}{f(x)}\frac{df}{dx}=$ the derivative on the right.

To find $\frac{df}{dx}$ differentiate on the right and multiply by $f(x)= \frac{x^3(x- 2)^3}{(x^2+ 8)^7}$.
• November 19th 2010, 02:55 PM
softballchick
thanks I got it!
• November 19th 2010, 03:04 PM
TheCoffeeMachine
Quote:

Originally Posted by softballchick
thanks I got it!

1. Be clear as to what you mean next time so as not to waste people's time.
2. Editing out posts after getting help isn't allowed, and it's a sign of cheating.