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Math Help - partial fractions

  1. #1
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    partial fractions

    Find  \int\frac{2x^4}{x^6-x^2}

    got denominator to:
     x^6 - x^2 = x^2(x^4-1) = x^2(x^2+1)(x^2-1)
    need a lil help from here
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  2. #2
    MHF Contributor red_dog's Avatar
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    \displaystyle \int\frac{2x^4}{x^6-x^2}dx=\int\frac{2x^4}{x^2(x^4-1)}dx=\int\frac{2x^2}{(x^2-1)(x^2+1)}dx=
    \displaystyle =\int\left(\frac{1}{x^2-1}+\frac{1}{x^2+1}\right)dx
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