. U=1/x du=lnxdx v=2^l/ln2 I= Is it good? "l" mean "lnx"
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Originally Posted by Kristina U=1/x du=lnxdx That is not right: . Better use the substitution . Then: Could you continue?. Regards. Fernando Revilla
Sorry, but I do not understand... WHy I can not do like this?
because ln(x) is the integral of 1/x, not the derivative. If u= 1/x then not "ln x dx". That is precisely what FernandoRevilla said before. Instead of integration by parts, use the simple substitution t= ln x that FernandoRevilla suggested.
Originally Posted by Kristina . U=1/x du=lnxdx v=2^l/ln2 I= Is it good? "l" mean "lnx" CB
t=lnx t=ln1=0
Originally Posted by Kristina t=lnx t=ln1=0 Is it good? or I'm wrong?
Originally Posted by Kristina Is it good? or I'm wrong? Regards. Fernando Revilla
You are collectivly making a meal of this: ............. CB
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