Having a bit of trouble, here is what i've done so far.
Last edited by rlkmg; Nov 17th 2010 at 01:25 PM.
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Originally Posted by rlkmg Having a bit of trouble, here is what i've done so far. So...?? What do you think you've proved so far? $\displaystyle \displaystyle{I_{n+1}:=\int\limits^1_0\frac{x^n}{2-x}\,dx=\int\limits^1_0\frac{x^{n-1}(2-(2-x))}{2-x}\,dx=2I_n-\int\limits^1_0x^{n-1}\,dx}$ , and we're done Tonio
$\displaystyle \int\limits^1_0x^{n-1}\,dx}$ thanks, I've got it now (the 2I(n) ) bit, but how do i get the above part to 1/n?
Originally Posted by rlkmg thanks, I've got it now (the 2I(n) ) bit, but how do i get the above part to 1/n? Just solve it! Tonio
ahh okay, got it now, thanks! silly, didnt see that
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