Find the value of $\displaystyle \displaystyle \int_{0}^{1}\frac{\arctan{t}}{\ln(1+t)}\,dt $$.
Hey I am new to this site but I was wondering what software you are using to display the integrals.
I looked at the problem and was going to propose a direction to try. If you do integration by parts you get u=arctan(x) dv= 1/ln(1+t)
I was thinking that 1/ln(1+t) might be a workable integral. What calculus level are you taking?
The "LaTex" software is built into the site. Look at the thread http://www.mathhelpforum.com/math-help/f47/