Use logarithms to solve the equation for t.
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1. Isolate $\displaystyle e^{t/2}$. 2. Take $\displaystyle \ln$ of both sides. 3. Multiply both sides by 2.
i have no clue...
Originally Posted by djdownfawl Use logarithms to solve the equation for t. $\displaystyle A = C(1+Be^{t/2}) = C + CBe^{t/2}$ Can you isolate $\displaystyle e^{t/2}$ now?
no...
Originally Posted by djdownfawl no... Look at it as if you were doing algebra. Once you get down to $\displaystyle e^{t/2}$, then take the logarithm of both sides and multiply both side by 2.
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